(4x^3+32)/(4x^4-64)

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Solution for (4x^3+32)/(4x^4-64) equation: 


D( x )

4*x^4-64 = 0

4*x^4-64 = 0

4*x^4-64 = 0

4*x^4 = 64 // : 4

x^4 = 16

x^4 = 16 // ^ 1/4

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

(4*x^3+32)/(4*x^4-64) = 0

4*x^3 = -32 // : 4

x^3 = -8

x^3 = -8 // ^ 1/3

x = -2

x in { -2} 

x belongs to the empty set

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